Ponzu Chicken Sandwich - cooking recipe

Ingredients

1 cup prepared ponzu sauce
1 cup chopped fresh cilantro
1/2 cup pineapple juice
4 fresh mint leaves, chopped
4 cloves garlic, crushed
1 tablespoon grated fresh ginger
1 tablespoon toasted sesame oil
1 tablespoon chili oil
1 teaspoon brown sugar
3 skinless, boneless chicken breast halves, cut into chunks
1 tablespoon olive oil
1 onion, sliced
1 red bell pepper, sliced
1 jalapeno pepper, sliced
salt and freshly ground black pepper to taste
1 small head cabbage, shredded
4 Italian-style hoagie buns, split lengthwise and toasted
12 slices Swiss cheese
1/4 cup chopped fresh cilantro, divided
1 tablespoon sesame seeds, divided
1 tablespoon chile-garlic sauce (such as Sriracha(R)), or to taste - divided
1 lime, cut into wedges

Preparation

Preheat oven to 500 degrees F (260 degrees C).
Combine ponzu sauce, 1 cup cilantro, pineapple juice, mint leaves, garlic, fresh ginger, sesame oil, chili oil, and brown sugar together in a large bowl. Add chicken and toss to coat.
Remove chicken from ponzu sauce mixture, reserving marinade. Heat large pot or Dutch oven over medium-high heat. Add chicken and cook, stirring frequently, until browned, about 5 minutes. Stir in olive oil, onion, red bell pepper, jalapeno pepper, salt, and black pepper. Cook and stir until onion has softened and turned translucent, about 5 minutes.
Pour reserved marinade into chicken mixture and bring to a boil. Stir in cabbage and cook until slightly wilted, 4 to 5 minutes.
Using a slotted spoon, transfer chicken mixture into toasted hoagie buns and top each sandwich with 3 slices Swiss cheese.
Place sandwiches onto a baking sheet and bake in the preheated oven until cheese is melted and buns are toasted, about 5 minutes. Garnish each sandwich with 2 tablespoons cilantro, 1/4 of the sesame seeds, and 1/4 of the chile-garlic sauce. Serve with lime wedges.